n=6n(n^2-n)+9n

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Solution for n=6n(n^2-n)+9n equation: 



n=6n(n^2-n)+9n

We move all terms to the left:

n-(6n(n^2-n)+9n)=0



We calculate terms in parentheses: -(6n(n^2-n)+9n), so:

6n(n^2-n)+9n

We add all the numbers together, and all the variables

9n+6n(n^2-n)

We multiply parentheses

6n^3-6n^2+9n

We do not support enpression: n^3

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